A transverse harmonic wave on a string is described by y = 3sin left( {36t + 0.018x + fra

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14.Waves and Sound

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A transverse harmonic wave on a string is described by $y = 3\sin \left( {36t + 0.018x + \frac{\pi }{4}} \right)$ where $x$ and $y$ are in $cm$ and $t$ in $s$. The least distance between two successive crests in the wave is .... $m$

A

$2.5$

B

$3.5$

C

$1.5$

D

$4.5$

Solution

$\mathrm{k}=.018$

$\lambda=2 \pi \mathrm{k}=\frac{2 \pi}{.018}=348.88=3.5 \mathrm{\,m}$

Standard 11

Physics

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